*All rights reserved including the right of reproduction in whole or in part in any form.Used by arrangement with Alpha Books, a member of Penguin Group (USA) Inc. Comparing this with y = mx c, we have: m = -\(\frac\) and c = - \(\frac\) Therefore, slope = -\(\frac\) and y-intercept = - \(\frac\) (ii) Determine the slope and y-intercept of the line 9x - 5y 2 = 0Solution: Here, 9x - 5y - 2 = 0 ⟹ -5y = -9x 2⟹ y = \(\frac\)x \(\frac\).⟹ y = \(\frac\)x - \(\frac\).*

*All rights reserved including the right of reproduction in whole or in part in any form.*Used by arrangement with Alpha Books, a member of Penguin Group (USA) Inc.

Solution: Remember, all you have to do to transform an equation into slope-intercept form is to solve it for y.

To isolate the y, subtract x from both sides of the equation and then divide everything by the coefficient of - 4: © 2004 by W.

You will see later, why the y-intercept is an important parameter in linear equations and you will also learn about the physical meaning of its value in certain real-world examples.

Still need to know how to find the slope intercept form of a linear equation?

The points (-2, 5) and (1, -4) are plotted in the x-y plane.

Find the slope and y-intercept of the line joining the points.(For example, you will find an at which the line crosses the y-axis.To find it, you have to substitute x = 0 in the linear equation.wiki How's Content Management Team carefully monitors the work from our editorial staff to ensure that each article meets our high quality standards. The slope intercept form calculator will teach you how to find the equation of a line from any two points that this line passes through.We will assume you know two points that the straight line goes through.The first one will have coordinates (x₁, y₁) and the second one (x₂, y₂).Draw the graph of 3x - √3y = 2√3 using its slope and y-intercept. Solution: Here, 3x - √3y = 2√3 ⟹ - √3y = -3x 2√3⟹ √3y = 3x - 2√3y = √3x – 2Comparing with y = mx c, we find the slope m = √3 and y-intercept = -2. Are you wondering why I asked you to solve the linear equations in the above exercises for y?I wasn't just making you jump through hoops (although I am impressed by your agility, I must admit); there's actually a very good reason to do it.

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